Difference between revisions of "2009 AMC 10B Problems/Problem 25"
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| − | {{duplicate|[[2009 AMC | + | {{duplicate|[[2009 AMC 10B Problems|2009 AMC 10B #25]] and [[2009 AMC 12B Problems|2009 AMC 12B #17]]}} |
== Problem == | == Problem == | ||
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<math>\boxed{\frac {3}{16}}</math>. The answer is <math>\mathrm{(B)}</math>. | <math>\boxed{\frac {3}{16}}</math>. The answer is <math>\mathrm{(B)}</math>. | ||
| + | {{AMC10 box|year=2009|ab=B|num-b=24|after=Last question}} | ||
{{AMC12 box|year=2009|ab=B|num-b=16|num-a=18}} | {{AMC12 box|year=2009|ab=B|num-b=16|num-a=18}} | ||
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Revision as of 14:43, 26 February 2009
- The following problem is from both the 2009 AMC 10B #25 and 2009 AMC 12B #17, so both problems redirect to this page.
Problem
Each face of a cube is given a single narrow stripe painted from the center of one edge to the center of the opposite edge. The choice of the edge pairing is made at random and independently for each face. What is the probability that there is a continuous stripe encircling the cube?
Solution
. The answer is 
.
| 2009 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 24 |
Followed by Last question | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
| 2009 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 16 |
Followed by Problem 18 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
