Difference between revisions of "2004 AMC 10B Problems/Problem 5"

(New page: D =0; A must be determined either 3 or 2. 3^2 > 2^3, thus A is 3. B then follows to be 2 and C = 1. The result is 9, (D))
 
 
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D =0;
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#redirect [[2004 AMC 12B Problems/Problem 2]]
A must be determined either 3 or 2.
 
3^2 > 2^3, thus A is 3.
 
B then follows to be 2 and C = 1.
 
The result is 9, (D)
 

Latest revision as of 12:22, 7 February 2009