Difference between revisions of "2002 AMC 10B Problems/Problem 13"
(2002 AMC 10B Problem 13) |
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+ | == Problem == | ||
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Find the value(s) of <math>x</math> such that <math>8xy - 12y + 2x - 3 = 0</math> is true for all values of <math>y</math>. | Find the value(s) of <math>x</math> such that <math>8xy - 12y + 2x - 3 = 0</math> is true for all values of <math>y</math>. | ||
<math>\textbf{(A) } \frac23 \qquad \textbf{(B) } \frac32 \text{ or } -\frac14 \qquad \textbf{(C) } -\frac23 \text{ or } -\frac14 \qquad \textbf{(D) } \frac34 \qquad \textbf{(E) } -\frac32 \text{ or } -\frac14</math> | <math>\textbf{(A) } \frac23 \qquad \textbf{(B) } \frac32 \text{ or } -\frac14 \qquad \textbf{(C) } -\frac23 \text{ or } -\frac14 \qquad \textbf{(D) } \frac34 \qquad \textbf{(E) } -\frac32 \text{ or } -\frac14</math> | ||
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+ | == Solution == | ||
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+ | We have <math>8xy - 12y + 2x - 3 = 4y(2x - 3) + (2x - 3) = (4y + 1)(2x - 3)</math>. | ||
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+ | As <math>(4y + 1)(2x - 3) = 0</math> must be true for all <math>y</math>, we must have <math>2x - 3 = 0</math>, hence <math>\boxed{x = \frac 32}</math>. | ||
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+ | (Too bad there is no such option -- maybe a typo when transcribing the options? Or the question is not formulated correctly? Note that the other fraction in option <math>B</math> would be the answer to the complementary question "find the value <math>y</math> such that ... for all <math>x</math>".) | ||
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+ | == See Also == | ||
+ | |||
+ | {{AMC10 box|year=2002|ab=B|num-b=12|num-a=14}} |
Revision as of 06:35, 2 February 2009
Problem
Find the value(s) of such that is true for all values of .
Solution
We have .
As must be true for all , we must have , hence .
(Too bad there is no such option -- maybe a typo when transcribing the options? Or the question is not formulated correctly? Note that the other fraction in option would be the answer to the complementary question "find the value such that ... for all ".)
See Also
2002 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 12 |
Followed by Problem 14 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |