Difference between revisions of "2002 AMC 12B Problems/Problem 8"
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The answer is a day of the week that is guaranteed to fall on one of August 1, August 2, and August 3. We can easily see that the only such day of the week is <math>\boxed{\mathrm{Thursday}}</math> (August 1 in case 1, August 2 in case 2, and August 3 in case 3) <math>\Longrightarrow \mathrm{(D)}.</math> | The answer is a day of the week that is guaranteed to fall on one of August 1, August 2, and August 3. We can easily see that the only such day of the week is <math>\boxed{\mathrm{Thursday}}</math> (August 1 in case 1, August 2 in case 2, and August 3 in case 3) <math>\Longrightarrow \mathrm{(D)}.</math> | ||
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| + | ==See also== | ||
| + | {{AMC12 box|year=2002|ab=B|num-b=7|num-a=9}} | ||
Revision as of 19:09, 21 February 2010
Let 
be a 31-day month and 
a day of the week. We can easily see that occurs five times in if and only if one of the first three days of falls on a . This is because the 5th occurrence of is 28 days after the first one, so the only possibilities for their dates are 
, 
, and 
.
We now know that one of July 1, July 2 and July 3 was a Monday.
In these three cases, August 1 is a Thursday, a Wednesday, and a Tuesday.
The answer is a day of the week that is guaranteed to fall on one of August 1, August 2, and August 3. We can easily see that the only such day of the week is 
(August 1 in case 1, August 2 in case 2, and August 3 in case 3) 
See also
| 2002 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 7 |
Followed by Problem 9 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
