Difference between revisions of "2025 AIME II Problems/Problem 10"
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Case 1: 8 people are all by single: 8C0 * 9C1 = 9 | Case 1: 8 people are all by single: 8C0 * 9C1 = 9 | ||
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Case 2: 6 people are by single, 2 people sits next to each other (so each person sits next to either 0 or 1 other person): 7C1 * 9C2 = 7 * 36 = 252 | Case 2: 6 people are by single, 2 people sits next to each other (so each person sits next to either 0 or 1 other person): 7C1 * 9C2 = 7 * 36 = 252 | ||
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Case 3: 4 people are by single, 2 people sits next to each other and 2 other people sits next to each other with the 2 groups of 2 people not sitting next to each other (so each person still sits next to either 0 or 1 other person): 6C2 * 9C3 = 1260 | Case 3: 4 people are by single, 2 people sits next to each other and 2 other people sits next to each other with the 2 groups of 2 people not sitting next to each other (so each person still sits next to either 0 or 1 other person): 6C2 * 9C3 = 1260 | ||
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Case 4: 2 people are by single, 6 people are split into 3 groups of 2 people, and no 2 groups sit next to each other: 5C3 * 9C4 = 10 * 126 = 1260 | Case 4: 2 people are by single, 6 people are split into 3 groups of 2 people, and no 2 groups sit next to each other: 5C3 * 9C4 = 10 * 126 = 1260 | ||
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Case 5: 4 groups of 2, no groups are sitting next to each other: 4C4 * 9C5 = 126 | Case 5: 4 groups of 2, no groups are sitting next to each other: 4C4 * 9C5 = 126 | ||
Revision as of 22:51, 13 February 2025
Problem
Sixteen chairs are arranged in a row. Eight people each select a chair in which to sit so that no person sits next to two other people. Let 
be the number of subsets of 
chairs that could be selected. Find the remainder when is divided by 
.
Solution 1: Caseworks
We split into few cases:
Case 1: 8 people are all by single: 8C0 * 9C1 = 9
Case 2: 6 people are by single, 2 people sits next to each other (so each person sits next to either 0 or 1 other person): 7C1 * 9C2 = 7 * 36 = 252
Case 3: 4 people are by single, 2 people sits next to each other and 2 other people sits next to each other with the 2 groups of 2 people not sitting next to each other (so each person still sits next to either 0 or 1 other person): 6C2 * 9C3 = 1260
Case 4: 2 people are by single, 6 people are split into 3 groups of 2 people, and no 2 groups sit next to each other: 5C3 * 9C4 = 10 * 126 = 1260
Case 5: 4 groups of 2, no groups are sitting next to each other: 4C4 * 9C5 = 126
Answer: 9 + 252 + 1260 + 1260 + 126 = 2907, so the answer is 907.
(Feel free to correct any format/latex problems)
~Mitsuihisashi14
