Difference between revisions of "2008 AMC 12B Problems/Problem 5"
(New page: ==Problem 5== A class collects <math>50</math> dollars to buy flowers for a classmate who is in the hospital. Roses cost <math>3</math> dollars each, and carnations cost <math>2</math> dol...) |
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==Solution== | ==Solution== | ||
The class could send just carnations (25 of them). They could also send 22 carnations and 2 roses, 19 carnations and 4 roses, and so on, down to 1 carnation and 16 roses. There are 9 total possibilities (from 0 to 16 roses, incrementing by 2 at each step), which is answer choice C. | The class could send just carnations (25 of them). They could also send 22 carnations and 2 roses, 19 carnations and 4 roses, and so on, down to 1 carnation and 16 roses. There are 9 total possibilities (from 0 to 16 roses, incrementing by 2 at each step), which is answer choice C. | ||
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| + | ==See Also== | ||
| + | {{AMC12 box|year=2008|ab=B|num-b=4|num-a=6}} | ||
Revision as of 22:01, 1 March 2008
Problem 5
A class collects 
dollars to buy flowers for a classmate who is in the hospital. Roses cost 
dollars each, and carnations cost 
dollars each. No other flowers are to be used. How many different bouquets could be purchased for exactly dollars?
Solution
The class could send just carnations (25 of them). They could also send 22 carnations and 2 roses, 19 carnations and 4 roses, and so on, down to 1 carnation and 16 roses. There are 9 total possibilities (from 0 to 16 roses, incrementing by 2 at each step), which is answer choice C.
See Also
| 2008 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 4 |
Followed by Problem 6 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
