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Difference between revisions of "2005 iTest Problems/Problem 4"

(Created page with "Taking one factor of <math>2005</math> as a base multiple, the other is split into <math>5 ^1 \cdot{ 401 ^1} = 2005</math>. This means <math>2005</math> has <math>(1 + 1)\cdot...")
 
 
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Taking one factor of <math>2005</math> as a base multiple, the other is split into <math>5 ^1 \cdot{ 401 ^1} = 2005</math>. This means <math>2005</math> has <math>(1 + 1)\cdot{(1 + 1)} = 4</math> divisors. Each of these divisors can be multiplied with the base multiple of <math>2005</math>, meaning the answer is <math>\boxed{4}</math>
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Taking one factor of <math>2005</math> as a base, the other is split into <math>5 ^1 \cot{ 401 ^1} = 2005</math>. This means <math>2005</math> has <math>(1 + 1)\cdot{(1 + 1)} = 4</math> divisors. Each of these divisors represents a multiple of <math>2005</math>, meaning the answer is <math>\boxed{4}</math>

Latest revision as of 02:50, 9 December 2024

Taking one factor of $2005$ as a base, the other is split into $5 ^1 \cot{ 401 ^1} = 2005$. This means $2005$ has $(1 + 1)\cdot{(1 + 1)} = 4$ divisors. Each of these divisors represents a multiple of $2005$, meaning the answer is $\boxed{4}$

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