Difference between revisions of "2024 AMC 12A Problems/Problem 19"

(solution 1)
(solution 1)
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<cmath>BD=\frac{39}{7}</cmath>
 
<cmath>BD=\frac{39}{7}</cmath>
 
Since <math>\frac{39}{7}<5</math>
 
Since <math>\frac{39}{7}<5</math>
The answer is <math>\fbox{(D) \frac{39}{7}}</math>
+
The answer is <math>\fbox{(D) \frac{39}{7} }</math>

Revision as of 18:03, 8 November 2024

solution 1

$\angle CBA=60 ^\circ$ by Circle Theorem} Let $AC=u$, apply cosine law on $\triangle ACD$ \[u^2=3^2+5^2-2(3)(5)cos120\] \[u=7\] Let $AB=v$, apply cosine law on $\triangle ABC$ \[7^2=3^2+v^2-2(3)(v)cos60\] \[v=\frac{3\pm13}{2}\] \[v=8\] By Ptolemy Theorem, \[AB \cdot CD+AD \cdot BC=AC \cdot BD\] \[8 \cdot 3+5 \cdot 3=7BD\] \[BD=\frac{39}{7}\] Since $\frac{39}{7}<5$ The answer is $\fbox{(D) \frac{39}{7} }$ (Error compiling LaTeX. Unknown error_msg)