Difference between revisions of "2006 AMC 8 Problems/Problem 8"
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Thus, the percentage of males surveyed that listen to the station is <math> 100 \cdot \frac{78}{104} \%= \boxed{\textbf{(E)}\ 75 \%} </math>. | Thus, the percentage of males surveyed that listen to the station is <math> 100 \cdot \frac{78}{104} \%= \boxed{\textbf{(E)}\ 75 \%} </math>. | ||
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| + | == Soulution 2 == | ||
| + | Instead of filling out the entire chart, you can find the number of male listeners which is 200 - 96 = 104. Since we know the fraction of males that don't listen to the station is <math> \frac{26}{104} </math>, we know that the percent of males that do listen is much larger than 50%, so the only answer is <math>\boxed{\textbf{(E)}\ 75 \%} </math>. | ||
==Video Solution by WhyMath== | ==Video Solution by WhyMath== | ||
Revision as of 00:47, 12 January 2025
Problem
The table shows some of the results of a survey by radiostation KACL. What percentage of the males surveyed listen to the station?
Solution
Filling out the chart, it becomes
Thus, the percentage of males surveyed that listen to the station is 
.
Soulution 2
Instead of filling out the entire chart, you can find the number of male listeners which is 200 - 96 = 104. Since we know the fraction of males that don't listen to the station is 
, we know that the percent of males that do listen is much larger than 50%, so the only answer is 
.
Video Solution by WhyMath
See Also
| 2006 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 7 |
Followed by Problem 9 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
