Difference between revisions of "1990 USAMO Problems/Problem 1"
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Revision as of 15:11, 13 January 2012
Problem
A certain state issues license plates consisting of six digits (from 0 through 9). The state requires that any two plates differ in at least two places. (Thus the plates 
and 
cannot both be used.) Determine, with proof, the maximum number of distinct license plates that the state can use.
Solutions
Consider license plates of 
digits, for some fixed , issued with the same criteria.
We first note that by the pigeonhole principle, we may have at most 
distinct plates. Indeed, if we have more, then there must be two plates which agree on the first 
plates; these plates thus differ only on one digit, the last one.
We now show that it is possible to issue distinct license plates which satisfy the problem's criteria. Indeed, we issue plates with all possible combinations for the first digit, and for each plate, we let the last digit be the sum of the preceding digits taken mod 10. This way, if two plates agree on the first digits, they agree on the last digit and are thus the same plate, and if two plates differ in only one of the first digits, they must differ as well in the last digit.
It then follows that is the greatest number of license plates the state can issue. For 
, as in the problem, this number is 
. 
Alternate solutions are always welcome. If you have a different, elegant solution to this problem, please add it to this page.
Tsh is awesome.
See also
| 1990 USAMO (Problems • Resources) | ||
| Preceded by First question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 | ||
| All USAMO Problems and Solutions | ||
