Difference between revisions of "1951 AHSME Problems/Problem 16"
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The [[discriminant]] of the quadratic equation is <math>b^2 - 4ac = b^2 - 4a\left(\frac{b^2}{4a}\right) = 0</math>. This indicates that the equation has only one root (applying the quadratic formula, we get <math>x = \frac{-b + \sqrt{0}}{2a} = -b/2a</math>). Thus it follows that <math>f(x)</math> touches the x-axis exactly once, and hence is tangent to the x-axis <math>\Rightarrow \mathrm{(C)}</math>. | The [[discriminant]] of the quadratic equation is <math>b^2 - 4ac = b^2 - 4a\left(\frac{b^2}{4a}\right) = 0</math>. This indicates that the equation has only one root (applying the quadratic formula, we get <math>x = \frac{-b + \sqrt{0}}{2a} = -b/2a</math>). Thus it follows that <math>f(x)</math> touches the x-axis exactly once, and hence is tangent to the x-axis <math>\Rightarrow \mathrm{(C)}</math>. | ||
− | == See | + | == See Also == |
− | {{AHSME box|year=1951|num-b=15|num-a=17}} | + | {{AHSME 50p box|year=1951|num-b=15|num-a=17}} |
[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] |
Revision as of 07:55, 29 April 2012
Problem
If in applying the quadratic formula to a quadratic equation
it happens that , then the graph of will certainly:
Solution
The discriminant of the quadratic equation is . This indicates that the equation has only one root (applying the quadratic formula, we get ). Thus it follows that touches the x-axis exactly once, and hence is tangent to the x-axis .
See Also
1951 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 15 |
Followed by Problem 17 | |
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All AHSME Problems and Solutions |