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Difference between revisions of "1959 AHSME Problems/Problem 27"

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== Solution ==
 
== Solution ==
  
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The sum of the roots can be calculated by <math>-\frac{b}{a}</math>. For this equation, that is <math>\frac{1}{i} = -i</math>, which is not <math>2</math>, so the solution is <math>\boxed{A}</math>.
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By [[Vieta's Formulas]], the sum of the roots is <math>\frac{1}{i} = -i</math>, which is not <math>2</math>, so the solution is <math>\fbox{\textbf{(A)}}</math>.
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== See also ==
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{{AHSME 50p box|year=1959|num-b=26|num-a=28}}
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{{MAA Notice}}

Latest revision as of 12:29, 21 July 2024

Problem

Which one of the following is not true for the equation $ix^2-x+2i=0$, where $i=\sqrt{-1}$ $\textbf{(A)}\ \text{The sum of the roots is 2} \qquad \\ \textbf{(B)}\ \text{The discriminant is 9}\qquad \\ \textbf{(C)}\ \text{The roots are imaginary}\qquad \\ \textbf{(D)}\ \text{The roots can be found using the quadratic formula}\qquad \\ \textbf{(E)}\ \text{The roots can be found by factoring, using imaginary numbers}$

Solution

By Vieta's Formulas, the sum of the roots is $\frac{1}{i} = -i$, which is not $2$, so the solution is $\fbox{\textbf{(A)}}$.

See also

1959 AHSC (Problems • Answer Key • Resources)
Preceded by
Problem 26 		Followed by
Problem 28
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50
All AHSME Problems and Solutions

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