Difference between revisions of "1970 AMC 12 Problems/Problem 2"
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A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is | A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is | ||
| − | <math>\mathrm{(A)}\ \frac 2\pi\qquad \mathrm{(B)}\ \frac \ | + | <math>\mathrm{(A)}\ \frac{2}{\pi}\qquad \mathrm{(B)}\ \frac{\pi}{\sqrt{2}}\qquad \mathrm{(C)}\ \frac{4}{5}\qquad \mathrm{(D)}\ \frac{5}{6}\qquad \mathrm{(E)}\ \frac{7}{8}</math> |
== Solution == | == Solution == | ||
Revision as of 14:09, 9 January 2008
Problem
A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is
