Difference between revisions of "Limit"

(Could someone check me on this plz? I'm trying to get through calculus, so feel free to improve it or delete it at will.)
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==Left and Right Hand Limits==
 
==Left and Right Hand Limits==
Left and Right hand limits are what they seem to be: limits from the left, and limits from the right. The left hand limit is in the form <math>\lim_{x\to c^{-}} f(x)</math>, and the right hand limit is in the form <math>\lim_{x\to c^{+}} f(x)</math>, since the left side of the [[Cartesian Coordinate]] [[plane]] is negative, and the right hand side is positive.
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Left and Right hand limits are what they seem to be: limits from the left, and limits from the right. The left hand limit is in the form <math>\lim_{x\to c^{-}} f(x)</math>, and the right hand limit is in the form <math>\lim_{x\to c^{+}} f(x)</math>, since the left side of the [[Cartesian coordinate system]] is negative, and the right hand side is positive.
  
 
==Existence of Limits==
 
==Existence of Limits==

Revision as of 13:56, 8 January 2008

Given a real or complex function $f(x)$ and some value $c$, the limit $\lim_{x\to c} f(x)$ of $f(x)$ as $x$ goes to $c$ is defined to be equal to the (real or complex) number $L$ if and only if for every $\epsilon > 0$ there exists a $\delta \in \mathbb R$ such that if $0<|x-c|<\delta$ then $|f(x)-L|< \epsilon$.

Intuitive Meaning

The formal definition of a limit given above is not necessarily easy to understand. We can instead offer the following informal explanation: a limit is the value to which the function grows close. For example, $\lim_{x\rightarrow 2}x^2=4$, because whenever $x$ is close to 2, the function $f(x)=x^2$ grows close to 4. In this case, the limit of the function is exactly equal to the value of the function. That is, $\lim_{x\rightarrow c} f(x) = f(c)$. This is because the function we chose was a continuous function. However, not all functions have this property. For example, consider the function $f(x)$ over the reals defined to be 0 if $x\neq 0$ and 1 if $x=0$. Although the value of the function at 0 is 1, the limit $\lim_{x\rightarrow 0}f(x)$ is, in fact, zero. Intuitively, this is because no matter how close we get to zero, as long as we never actually reach zero, $f(x)$ will always be close to (in fact equal to) zero. Note that if our definition required only that $|x-c|<\delta$, the limit of this function would not exist.

Left and Right Hand Limits

Left and Right hand limits are what they seem to be: limits from the left, and limits from the right. The left hand limit is in the form $\lim_{x\to c^{-}} f(x)$, and the right hand limit is in the form $\lim_{x\to c^{+}} f(x)$, since the left side of the Cartesian coordinate system is negative, and the right hand side is positive.

Existence of Limits

Limits do not always exist. For example $\lim_{x\rightarrow 0}\frac{1}{x}$ does not exist, since, in fact, there exists no $\epsilon$ for which there exists $\delta$ satisfying the definition's conditions, since $\left|\frac{1}{x}\right|$ grows arbitrarily large as $x$ approaches 0. However, it is possible for $\lim_{x\rightarrow c} f(x)$ not to exist even when $f$ is defined at $c$. For example, consider the Dirichlet function, $D(x)$, defined to be 0 when $x$ is irrational, and 1 when $x$ is rational. Here, $\lim_{x\rightarrow c}D(x)$ does not exist for any value of $c$. Alternatively, limits can exist where a function is not defined, as for the function $f(x)$ defined to be 1, but only for nonzero reals. Here, $\lim_{x\rightarrow 0}f(x)=1$, since for $x$ arbitrarily close to 0, $f(x)=1$.

A limit exists if the left and right hand side limits exist, and are equal.

Other Properties

Let $f$ and $g$ be real functions. Then:

  • $\lim(f+g)(x)=\lim f(x)+\lim g(x)$
  • $\lim(f-g)(x)=\lim f(x)-\lim g(x)$
  • $\lim(f\cdot g)(x)=\lim f(x)\cdot\lim g(x)$
  • $\lim\left(\frac{f}{g}\right)(x)=\frac{\lim f(x)}{\lim g(x)}$ given that $\lim g(x)\ne 0$.
  • If a limit exists, it is unique.

See Also