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Difference between revisions of "2016 AMC 8 Problems/Problem 7"
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==Solution 1==
 
==Solution 1==
 
Our answer must have an odd exponent in order for it to not be a square.  Because <math>4</math> is a perfect square, <math>4^{2019}</math> is also a perfect square, so our answer is <math>\boxed{\textbf{(B) }2^{2017}}</math>.
 
Our answer must have an odd exponent in order for it to not be a square.  Because <math>4</math> is a perfect square, <math>4^{2019}</math> is also a perfect square, so our answer is <math>\boxed{\textbf{(B) }2^{2017}}</math>.
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==Video Solution==
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 +
https://youtu.be/ymZQgW-cL4s?si=NbFD5ZIPgtojqEaj
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A solution so simple a 12-year-old made it!
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 +
~Elijahman~
  
 
==Video Solution (CREATIVE THINKING!!!)==
 
==Video Solution (CREATIVE THINKING!!!)==
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~Education, the Study of Everything
 
~Education, the Study of Everything
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==Video Solution==
 
==Video Solution==

Latest revision as of 10:47, 20 June 2024

Problem

Which of the following numbers is not a perfect square?

$\textbf{(A) }1^{2016}\qquad\textbf{(B) }2^{2017}\qquad\textbf{(C) }3^{2018}\qquad\textbf{(D) }4^{2019}\qquad \textbf{(E) }5^{2020}$

Solution 1

Our answer must have an odd exponent in order for it to not be a square. Because $4$ is a perfect square, $4^{2019}$ is also a perfect square, so our answer is $\boxed{\textbf{(B) }2^{2017}}$.

Video Solution

https://youtu.be/ymZQgW-cL4s?si=NbFD5ZIPgtojqEaj

A solution so simple a 12-year-old made it!

~Elijahman~

Video Solution (CREATIVE THINKING!!!)

https://youtu.be/_zfiULRR3co

~Education, the Study of Everything

Video Solution

https://www.youtube.com/watch?v=BZKzpY_pH5A ~David

https://youtu.be/prtDHdc12cs

~savannahsolver

See Also

2016 AMC 8 (Problems • Answer Key • Resources)
Preceded by
Problem 6 		Followed by
Problem 8
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

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