Difference between revisions of "2024 AMC 8 Problems/Problem 2"

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~ le_petit_chouetteur from TSMV
 
~ le_petit_chouetteur from TSMV
  
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==Video Solution by Math-X (First understand the problem!!!)==
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https://youtu.be/BaE00H2SHQM?si=noTBPTosCtH31CpW&t=287
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~Math-X
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2024|num-b=1|num-a=3}}
 
{{AMC8 box|year=2024|num-b=1|num-a=3}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 03:43, 13 February 2024

Problem 2

What is the value of this expression in decimal form? \[\frac{44}{11} + \frac{110}{44} + \frac{44}{1100}\] $\textbf{(A) } 6.4\qquad\textbf{(B) } 6.504\qquad\textbf{(C) } 6.54\qquad\textbf{(D) } 6.9\qquad\textbf{(E) } 6.94$

Solution 1

We see that 44/11 is 4; 110/44 simplifies to 5/2, which is 2.5;

and 44/1100 simplifies to 1/25, which is 0.04;

4+2.5+0.04 reveals \[\frac{44}{11} + \frac{110}{44} + \frac{44}{1100}\] is $\boxed{\textbf{(C)\ 6.54}}$. ~ le_petit_chouetteur from TSMV

Video Solution by Math-X (First understand the problem!!!)

https://youtu.be/BaE00H2SHQM?si=noTBPTosCtH31CpW&t=287

~Math-X

See Also

2024 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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