Difference between revisions of "2024 AMC 8 Problems/Problem 2"

(Video Solution by Math-X (First fully understand the problem!!!))
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Knock knock
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==Problem 2 ==
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What is the value of this expression in decimal form?
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<cmath>\frac{44}{11} + \frac{110}{44} + \frac{44}{1100}</cmath>
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<math>\textbf{(A) } 6.4\qquad\textbf{(B) } 6.504\qquad\textbf{(C) } 6.54\qquad\textbf{(D) } 6.9\qquad\textbf{(E) } 6.94</math>
  
whos there
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==Solution 1==
  
your mom
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We see that 44/11 is 4;
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110/44 simplifies to 5/2, which is 2.5;
  
your mom who
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and 44/1100 simplifies to 1/25, which is 0.04;
  
nothing thats literally the entire joke
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4+2.5+0.04 reveals <cmath>\frac{44}{11} + \frac{110}{44} + \frac{44}{1100}</cmath> is <math>\boxed{\textbf{(C)\ 6.54}}</math>.
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~ le_petit_chouetteur from TSMV
  
Answer is B
 
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2024|num-b=1|num-a=3}}
 
{{AMC8 box|year=2024|num-b=1|num-a=3}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 12:37, 11 February 2024

Problem 2

What is the value of this expression in decimal form? \[\frac{44}{11} + \frac{110}{44} + \frac{44}{1100}\] $\textbf{(A) } 6.4\qquad\textbf{(B) } 6.504\qquad\textbf{(C) } 6.54\qquad\textbf{(D) } 6.9\qquad\textbf{(E) } 6.94$

Solution 1

We see that 44/11 is 4; 110/44 simplifies to 5/2, which is 2.5;

and 44/1100 simplifies to 1/25, which is 0.04;

4+2.5+0.04 reveals \[\frac{44}{11} + \frac{110}{44} + \frac{44}{1100}\] is $\boxed{\textbf{(C)\ 6.54}}$. ~ le_petit_chouetteur from TSMV


See Also

2024 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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