Difference between revisions of "2024 AMC 8 Problems/Problem 14"

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(Solution 1)
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We can simply see that path <math>A \rightarrow X \rightarrow M \rightarrow Y \rightarrow C \rightarrow Z</math> will give us the smallest value. Adding, <math>5+2+6+5+10 = \boxed{28}</math>. This is nice as it’s also the smallest value, solidifying our answer.
 
We can simply see that path <math>A \rightarrow X \rightarrow M \rightarrow Y \rightarrow C \rightarrow Z</math> will give us the smallest value. Adding, <math>5+2+6+5+10 = \boxed{28}</math>. This is nice as it’s also the smallest value, solidifying our answer.
  
~MaxyMoosy
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You can also simply brute-force it or sort of think ahead - for example, getting from A to M can be done <math>2</math> ways; <math>A \rightarrow X \rightarrow M</math> (<math>5+2</math>) or <math>A \rightarrow M (8)</math>, so you should take the shorter route (<math>5+2</math>). Another example is M to C, two ways - one is <math>6+5</math> and the other is <math>14</math>. Take the shorter route. After this, you need to consider a few more times - consider if <math>5+10</math> (<math>Y \rightarrow C \rightarrow Z</math>) is greater than <math>17 (Y \rightarrow Z</math>), which it is not, and consider if <math>25 (M \rightarrow Z</math>) is greater than <math>14+10</math> (<math>M \rightarrow C \rightarrow Z</math>) or <math>6+5+10</math> (<math>M \rightarrow Y \rightarrow C \rightarrow Z</math>) which it is not. TL;DR: <math>5+2=6=5=10 = \boxed{28}</math>. [Note: This is probably just the thinking behind the solution.] {Double-note: As MaxyMoosy said, since this answer is the smallest one, it has to be the right answer.}
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~MaxyMoosy ~HACKER2022
  
 
==Video Solution 1 (easy to digest) by Power Solve==
 
==Video Solution 1 (easy to digest) by Power Solve==

Revision as of 20:12, 29 January 2024

Problem

The one-way routes connecting towns $A,M,C,X,Y,$ and $Z$ are shown in the figure below(not drawn to scale).The distances in kilometers along each route are marked. Traveling along these routes, what is the shortest distance form A to Z in kilometers?

2024-AMC8-q14.png

$\textbf{(A)}\ 28 \qquad \textbf{(B)}\ 29 \qquad \textbf{(C)}\ 30 \qquad \textbf{(D)}\ 31 \qquad \textbf{(E)}\ 32$

Solution 1

We can simply see that path $A \rightarrow X \rightarrow M \rightarrow Y \rightarrow C \rightarrow Z$ will give us the smallest value. Adding, $5+2+6+5+10 = \boxed{28}$. This is nice as it’s also the smallest value, solidifying our answer.

You can also simply brute-force it or sort of think ahead - for example, getting from A to M can be done $2$ ways; $A \rightarrow X \rightarrow M$ ($5+2$) or $A \rightarrow M (8)$, so you should take the shorter route ($5+2$). Another example is M to C, two ways - one is $6+5$ and the other is $14$. Take the shorter route. After this, you need to consider a few more times - consider if $5+10$ ($Y \rightarrow C \rightarrow Z$) is greater than $17 (Y \rightarrow Z$), which it is not, and consider if $25 (M \rightarrow Z$) is greater than $14+10$ ($M \rightarrow C \rightarrow Z$) or $6+5+10$ ($M \rightarrow Y \rightarrow C \rightarrow Z$) which it is not. TL;DR: $5+2=6=5=10 = \boxed{28}$. [Note: This is probably just the thinking behind the solution.] {Double-note: As MaxyMoosy said, since this answer is the smallest one, it has to be the right answer.}

~MaxyMoosy ~HACKER2022

Video Solution 1 (easy to digest) by Power Solve

https://youtu.be/2AVrraozwF8

Video Solution 2 by SpreadTheMathLove

https://www.youtube.com/watch?v=RRTxlduaDs8

Video Solution 3 by NiuniuMaths (Easy to understand!)

https://www.youtube.com/watch?v=V-xN8Njd_Lc

~NiuniuMaths

Video Solution by CosineMethod [🔥Fast and Easy🔥]

https://www.youtube.com/watch?v=bAxLRYT6SCw

See Also

2024 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 13
Followed by
Problem 15
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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