Difference between revisions of "2024 AMC 8 Problems/Problem 6"

(Solution 1 (Analysis))
(Solution 1 (Analysis))
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==Problem==
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Sergai skated around an ice rink, gliding along different paths. The gray lines in the figures below show foru of the paths labeled <math>P</math>, <math>Q</math>, <math>R</math>, and <math>S</math>. What is the sorted order of the four paths from shortest to longest?
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<math>\textbf{(A)}\ P,Q,R,S \qquad \textbf{(B)}\ P,R,S,Q \qquad \textbf{(C)}\ Q,S,P,R \qquad \textbf{(D)}\ R,P,S,Q \qquad \textbf{(E)}\ R,S,P,Q</math>
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==Solution 1 (Analysis)==
 
==Solution 1 (Analysis)==
  

Revision as of 17:14, 25 January 2024

Problem

Sergai skated around an ice rink, gliding along different paths. The gray lines in the figures below show foru of the paths labeled $P$, $Q$, $R$, and $S$. What is the sorted order of the four paths from shortest to longest?

$\textbf{(A)}\ P,Q,R,S \qquad \textbf{(B)}\ P,R,S,Q \qquad \textbf{(C)}\ Q,S,P,R \qquad \textbf{(D)}\ R,P,S,Q \qquad \textbf{(E)}\ R,S,P,Q$

Solution 1 (Analysis)

$R$ skips around the boundary of the rink, while $P$ goes around the whole boundary. Hence, the length of path $R$ is less than the length of path $P$. Now, using the fact that the hypotenuse of a right triangle is greater than both of its legs, it is clear that the path described in $S$ is longer than $P$. Finally, each V-shaped zag path from path $Q$ is longer than a diagonal in path $S$, so the length of path $Q$ is greater than that of $S$. Collectively, we obtain the answer $\boxed{\textbf{(D)}~R, P, S, Q}$.

Video Solution 1(easy to digest) by Power Solve

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