Difference between revisions of "2024 AMC 8 Problems/Problem 5"
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==Solution 1== | ==Solution 1== | ||
− | Using the process of elimination, we can find the following: | + | Using the process of elimination, we can find the following: |
− | A is possible: <math>2 | + | |
− | C is possible: <math>1 | + | <math>\textbf{(A)}</math> is possible: <math>2\times 3</math> |
− | D is possible: <math>2 | + | |
− | E is possible: <math>3 | + | <math>\textbf{(C)}</math> is possible: <math>1\times 6</math> |
− | + | ||
− | -ILoveMath31415926535 | + | <math>\textbf{(D)}</math> is possible: <math>2\times 6</math> |
+ | |||
+ | <math>\textbf{(E)}</math> is possible: <math>3\times 6</math> | ||
+ | |||
+ | The only integer that cannot be the sum is <math>\boxed{\textbf{(B)\ 6}}.</math> | ||
+ | |||
+ | -ILoveMath31415926535 & countmath1 | ||
==Video Solution 1 (easy to digest) by Power Solve== | ==Video Solution 1 (easy to digest) by Power Solve== | ||
https://youtu.be/HE7JjZQ6xCk?si=2M33-oRy1ExY3_6l&t=239 | https://youtu.be/HE7JjZQ6xCk?si=2M33-oRy1ExY3_6l&t=239 |
Revision as of 12:37, 26 January 2024
Problem
Aaliyah rolls two standard 6-sided dice. She notices that the product of the two numbers rolled is a multiple of . Which of the following integers cannot be the sum of the two numbers?
Solution 1
Using the process of elimination, we can find the following:
is possible:
is possible:
is possible:
is possible:
The only integer that cannot be the sum is
-ILoveMath31415926535 & countmath1