Difference between revisions of "2024 AMC 8 Problems/Problem 5"
(→Problem) |
(→Solution 1) |
||
Line 5: | Line 5: | ||
==Solution 1== | ==Solution 1== | ||
+ | Trial and Error: | ||
+ | |||
+ | We know that 7 = 6 + 1, 8 = 6 + 2, and 9 = 6 + 3 meaning that they are not the solutions because 6 x 1 = 6, 6 x 2 = 12, and 6 x 3 = 18 | ||
+ | |||
+ | Next, we know that 5 = 2 + 3 and 2 x 3 = 6 meaning that with process of elimination the answer must be 6 | ||
+ | |||
+ | You can check by seeing all the numbers that add to 6, 1 + 5, 2 + 4, and 3 + 3. |
Revision as of 13:48, 25 January 2024
Problem
Aaliyah rolls two standard 6-sided dice. She notices that the product of the two numbers rolled is a multiple of . Which of the following integers cannot be the sum of the two numbers?
Solution 1
Trial and Error:
We know that 7 = 6 + 1, 8 = 6 + 2, and 9 = 6 + 3 meaning that they are not the solutions because 6 x 1 = 6, 6 x 2 = 12, and 6 x 3 = 18
Next, we know that 5 = 2 + 3 and 2 x 3 = 6 meaning that with process of elimination the answer must be 6
You can check by seeing all the numbers that add to 6, 1 + 5, 2 + 4, and 3 + 3.