Difference between revisions of "2024 AMC 8 Problems/Problem 1"

(Problem)
(Solution 1)
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<math>\textbf{(A) } 0\qquad\textbf{(B) } 2\qquad\textbf{(C) } 4\qquad\textbf{(D) } 6\qquad\textbf{(E) } 8</math>
 
<math>\textbf{(A) } 0\qquad\textbf{(B) } 2\qquad\textbf{(C) } 4\qquad\textbf{(D) } 6\qquad\textbf{(E) } 8</math>
  
==Solution==
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==Solution 1==
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 +
<cmath>222,222-22,222-2,222-222-22-2</cmath>
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<cmath> \equiv 2-2-2-2-2-2</cmath>
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<cmath> \equiv -8</cmath>
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So the solution is <math>(E)</math>  <math>8</math>

Revision as of 12:59, 25 January 2024

Problem

What is the ones digit of \[222,222-22,222-2,222-222-22-2?\] $\textbf{(A) } 0\qquad\textbf{(B) } 2\qquad\textbf{(C) } 4\qquad\textbf{(D) } 6\qquad\textbf{(E) } 8$

Solution 1

\[222,222-22,222-2,222-222-22-2\] \[\equiv 2-2-2-2-2-2\] \[\equiv -8\] So the solution is $(E)$ $8$