Difference between revisions of "1999 AMC 8 Problems/Problem 16"
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To get a <math>60\%</math> on her test overall, she needed to get <math>60\% \cdot 75 = 0.60 \cdot 75 = 45</math> questions right. | To get a <math>60\%</math> on her test overall, she needed to get <math>60\% \cdot 75 = 0.60 \cdot 75 = 45</math> questions right. | ||
| − | Therefore, she needed to answer <math>45 - 40 = 5</math> more questions to pass, so the correct answer is <math>\boxed{B 5}</math> | + | Therefore, she needed to answer <math>45 - 40 = 5</math> more questions to pass, so the correct answer is <math>\boxed{(B) 5}</math> |
==Video Solution== | ==Video Solution== | ||
Latest revision as of 19:30, 11 January 2024
Contents
Problem
Tori's mathematics test had 75 problems: 10 arithmetic, 30 algebra, and 35 geometry problems. Although she answered 70% of the arithmetic, 40% of the algebra, and 60% of the geometry problems correctly, she did not pass the test because she got less than 60% of the problems right. How many more problems would she have needed to answer correctly to earn a 60% passing grade?
Solution
First, calculate how many of each type of problem she got right:
Arithmetic: 
Algebra: 
Geometry: 
Altogether, Tori answered 
questions correct.
To get a 
on her test overall, she needed to get 
questions right.
Therefore, she needed to answer 
more questions to pass, so the correct answer is 
Video Solution
https://youtu.be/3sBMI9cVhNs Soo, DRMS, NM
See Also
| 1999 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 15 |
Followed by Problem 17 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
