Difference between revisions of "2002 AMC 12P Problems/Problem 17"
(→Solution) |
(→Solution 2 (Cheese)) |
||
| Line 17: | Line 17: | ||
== Solution 2 (Cheese)== | == Solution 2 (Cheese)== | ||
| − | We don't actually have to solve the question. Just let <math>x</math> equal some easy value to calculate <math>\cos {x}, \cos {2x},</math> and <math>\cos {\frac{x}{2}}.</math> For this solution, let <math>x=60^\circ.</math> This means that the expression in the problem will give | + | We don't actually have to solve the question. Just let <math>x</math> equal some easy value to calculate <math>\cos {x}, \cos {2x}, \sin {x}, \sin {\frac{x}{2}}</math> and <math>\cos {\frac{x}{2}}.</math> For this solution, let <math>x=60^\circ.</math> This means that the expression in the problem will give |
== See also == | == See also == | ||
{{AMC12 box|year=2002|ab=P|num-b=16|num-a=18}} | {{AMC12 box|year=2002|ab=P|num-b=16|num-a=18}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 01:04, 31 December 2023
Problem
Let 
An equivalent form of 
is
Solution 2 (Cheese)
We don't actually have to solve the question. Just let 
equal some easy value to calculate 
and 
For this solution, let 
This means that the expression in the problem will give
See also
| 2002 AMC 12P (Problems • Answer Key • Resources) | |
| Preceded by Problem 16 |
Followed by Problem 18 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
