Difference between revisions of "2002 OIM Problems/Problem 5"

 
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The sequence of real numbers <math>a1, a2, \cdots</math> is defined as:
 
The sequence of real numbers <math>a1, a2, \cdots</math> is defined as:
  
<math></math>a_1 = 56, a_{n+1} = a_n - \frac{1}{a_n}
+
<cmath>a_1 = 56, a_{n+1} = a_n - \frac{1}{a_n}</cmath>
  
 
for every integer <math>n \ge 1</math>.
 
for every integer <math>n \ge 1</math>.

Latest revision as of 03:45, 14 December 2023

Problem

The sequence of real numbers $a1, a2, \cdots$ is defined as:

\[a_1 = 56, a_{n+1} = a_n - \frac{1}{a_n}\]

for every integer $n \ge 1$.

Prove that there exists an integer $k$, $1 \le k \le 2002$, such that $a_k < 0$.

~translated into English by Tomas Diaz. orders@tomasdiaz.com

Solution

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See also

https://www.oma.org.ar/enunciados/ibe18.htm