Difference between revisions of "2023 AMC 10B Problems/Problem 4"

(Solution)
m (Problem)
Line 3: Line 3:
 
Jackson's paintbrush makes a narrow strip with a width of 6.5 millimeters. Jackson has enough paint to make a strip 25 meters long. How many square centimeters of paper could Jackson cover with paint?  
 
Jackson's paintbrush makes a narrow strip with a width of 6.5 millimeters. Jackson has enough paint to make a strip 25 meters long. How many square centimeters of paper could Jackson cover with paint?  
  
<math>\textbf{(A) }162.5\qquad\textbf{(B) }1,625\qquad\textbf{(C) }16,250\qquad\textbf{(D) }162,500\qquad\textbf{(E) }1,625,000</math>
+
<math>\textbf{(A) }162,500\qquad\textbf{(B) }162.5\qquad\textbf{(C) }1,625\qquad\textbf{(D) }1,625,000\qquad\textbf{(E) }16,250</math>
  
 
==Solution==
 
==Solution==

Revision as of 17:03, 15 November 2023

Problem

Jackson's paintbrush makes a narrow strip with a width of 6.5 millimeters. Jackson has enough paint to make a strip 25 meters long. How many square centimeters of paper could Jackson cover with paint?

$\textbf{(A) }162,500\qquad\textbf{(B) }162.5\qquad\textbf{(C) }1,625\qquad\textbf{(D) }1,625,000\qquad\textbf{(E) }16,250$

Solution

$6.5$ mm = $0.65$ cm

$25$ m = $2500$ cm

$0.65\times2500=\boxed{\textbf{(B) }1,625}.$


~Mintylemon66