Difference between revisions of "2023 AMC 12B Problems/Problem 4"
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| + | {{duplicate|[[2023 AMC 10B Problems/Problem 4|2023 AMC 10B #4]] and [[2023 AMC 12B Problems/Problem 4|2023 AMC 12B #4]]}} | ||
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==Problem== | ==Problem== | ||
| − | Jackson's paintbrush makes a narrow strip with a width of 6.5 millimeters. Jackson has enough paint to make a strip long. How many square centimeters of paper could Jackson paint? | + | Jackson's paintbrush makes a narrow strip with a width of 6.5 millimeters. Jackson has enough paint to make a strip 25 meters long. How many square centimeters of paper could Jackson cover with paint? |
<math>\textbf{(A) } 162,500 \qquad\textbf{(B) } 162.5 \qquad\textbf{(C) }1,625 \qquad\textbf{(D) }1,625,000 \qquad\textbf{(E) } 16,250</math> | <math>\textbf{(A) } 162,500 \qquad\textbf{(B) } 162.5 \qquad\textbf{(C) }1,625 \qquad\textbf{(D) }1,625,000 \qquad\textbf{(E) } 16,250</math> | ||
| − | ==Solution | + | ==Solution== |
6.5 millimeters is equal to 0.65 centimeters. 25 meters is 2500 meters. The answer is <math>0.65 \times 2500</math>, so the answer is <math>\boxed{\textbf{(C) 1,625}}</math>. | 6.5 millimeters is equal to 0.65 centimeters. 25 meters is 2500 meters. The answer is <math>0.65 \times 2500</math>, so the answer is <math>\boxed{\textbf{(C) 1,625}}</math>. | ||
~Failure.net | ~Failure.net | ||
| + | ~Mintylemon66 | ||
| + | |||
| + | ==See also== | ||
| + | {{AMC10 box|year=2023|ab=B|num-b=3|num-a=5}} | ||
| + | {{AMC12 box|year=2023|ab=B|num-b=3|num-a=5}} | ||
| + | {{MAA Notice}} | ||
Revision as of 19:22, 15 November 2023
- The following problem is from both the 2023 AMC 10B #4 and 2023 AMC 12B #4, so both problems redirect to this page.
Problem
Jackson's paintbrush makes a narrow strip with a width of 6.5 millimeters. Jackson has enough paint to make a strip 25 meters long. How many square centimeters of paper could Jackson cover with paint?
Solution
6.5 millimeters is equal to 0.65 centimeters. 25 meters is 2500 meters. The answer is 
, so the answer is 
.
~Failure.net ~Mintylemon66
See also
| 2023 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
| 2023 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 3 |
Followed by Problem 5 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
