Difference between revisions of "2019 Mock AMC 10B Problems/Problem 8"
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| − | + | Solution 1: | |
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| + | the probability for each point will be the same if the points are equidistant from the origin because it will take the same amount of moves. There are 8 points inclusive of (4,3) --> (3,4),(-3,4),(-4,3),(3,-4),(4,-3), (-3,-4),(-4,-3) | ||
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| + | Therefore the solution is 8 | ||
Latest revision as of 16:51, 11 November 2023
Solution 1:
the probability for each point will be the same if the points are equidistant from the origin because it will take the same amount of moves. There are 8 points inclusive of (4,3) --> (3,4),(-3,4),(-4,3),(3,-4),(4,-3), (-3,-4),(-4,-3)
Therefore the solution is 8
