Difference between revisions of "2023 AMC 10A Problems/Problem 8"
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(I added solution 3, an easy to find, intuitive solution that is based on finding how much each Breadus unit is degrees Fahrenheit. This might be the wrong solution, but I did get the correct answer.) |
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~walmartbrian | ~walmartbrian | ||
− | ==Solution 2 ( | + | ==Solution 2 (Faster)== |
Let <math>^\circ B</math> denote degrees Breadus. We notice that <math>200^\circ F</math> is <math>90^\circ F</math> degrees to <math>0^\circ B</math>, and <math>150^\circ F</math> to <math>100^\circ B</math>. This ratio is <math>90:150=3:5</math>; therefore, <math>200^\circ F</math> will be <math>\dfrac3{3+5}=\dfrac38</math> of the way from <math>0</math> to <math>100</math>, which is <math>\boxed{\textbf{(D) }37.5.}</math> | Let <math>^\circ B</math> denote degrees Breadus. We notice that <math>200^\circ F</math> is <math>90^\circ F</math> degrees to <math>0^\circ B</math>, and <math>150^\circ F</math> to <math>100^\circ B</math>. This ratio is <math>90:150=3:5</math>; therefore, <math>200^\circ F</math> will be <math>\dfrac3{3+5}=\dfrac38</math> of the way from <math>0</math> to <math>100</math>, which is <math>\boxed{\textbf{(D) }37.5.}</math> | ||
~Technodoggo | ~Technodoggo | ||
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+ | ==Solution 3 (Intuitive)== | ||
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+ | From <math>110</math> to <math>350</math> degrees Fahrenheit, the Breadus scale goes from <math>1</math> to <math>100</math>. <math>110</math> to <math>350</math> degrees is a a span of <math>240</math>, and we can use this to determine how many Fahrenheit each Breadus unit is worth. <math>240</math> divided by <math>100</math> is <math>2.4</math>, so each Breadus unit is <math>2.4</math> Fahrenheit, starting at <math>110</math> Fahrenheit. For example, <math>1</math> degree on the Breadus scale is <math>110 + 2.4</math>, or <math>112.4</math> Fahrenheit. Using this information, we can figure out how many Breadus degrees <math>200</math> Fahrenheit is. <math>200-110</math> is <math>90</math>, so we divide <math>90</math> by <math>2.4</math> to find the answer, which is <math>\boxed{\textbf{(D) }37.5}</math> | ||
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+ | ~MercilessAnimations | ||
==See Also== | ==See Also== | ||
{{AMC10 box|year=2023|ab=A|num-b=7|num-a=9}} | {{AMC10 box|year=2023|ab=A|num-b=7|num-a=9}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 23:53, 9 November 2023
Problem
Barb the baker has developed a new temperature scale for her bakery called the Breadus scale, which is a linear function of the Fahrenheit scale. Bread rises at degrees Fahrenheit, which is degrees on the Breadus scale. Bread is baked at degrees Fahrenheit, which is degrees on the Breadus scale. Bread is done when its internal temperature is degrees Fahrenheit. What is this in degrees on the Breadus scale?
Solution 1
To solve this question, you can use where the is the Fahrenheit and the is the Breadus. We have and . We want to find . The slope for these two points is ; . Solving for using , . We get . Plugging in . Simplifying,
~walmartbrian
Solution 2 (Faster)
Let denote degrees Breadus. We notice that is degrees to , and to . This ratio is ; therefore, will be of the way from to , which is
~Technodoggo
Solution 3 (Intuitive)
From to degrees Fahrenheit, the Breadus scale goes from to . to degrees is a a span of , and we can use this to determine how many Fahrenheit each Breadus unit is worth. divided by is , so each Breadus unit is Fahrenheit, starting at Fahrenheit. For example, degree on the Breadus scale is , or Fahrenheit. Using this information, we can figure out how many Breadus degrees Fahrenheit is. is , so we divide by to find the answer, which is
~MercilessAnimations
See Also
2023 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 9 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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