Difference between revisions of "2023 AMC 8 Problems/Problem 1"

Revision as of 12:20, 26 October 2023

Problem

What is the value of $(8 \times 4 + 2) - (8 + 4 \times 2)$ ?

$\textbf{(A)}\ 0 \qquad \textbf{(B)}\ 6 \qquad \textbf{(C)}\ 10 \qquad \textbf{(D)}\ 18 \qquad \textbf{(E)}\ 24$

Solution 1

By the order of operations, we have $(8 \times 4 + 2) - (8 + 4 \times 2) = (32+2) - (8+8) = 34 - 16 = \boxed{\textbf{(D)}\ 18}.$ ~apex304, TaeKim, peelybonehead, MRENTHUSIASM

Solution 2

We can simplify the expression above in another way: $(8 \times 4 + 2) - (8 + 4 \times 2)=8\times4+2-8-4\times2=32+2-8-8=34-16=\boxed{\textbf{(D)}\ 18}.$

~MathFun1000

Video Solution by Math-X (Smart and Simple)

https://youtu.be/Ku_c1YHnLt0?si=RarnomIDE4gELDM3&t=62 ~Math-X

Video Solution (How to Creatively Think!!!)

https://youtu.be/n2tl50HMkDw

~Education the Study of everything

Video Solution by Magic Square

https://youtu.be/-N46BeEKaCQ?t=5746

Video Solution by SpreadTheMathLove

https://www.youtube.com/watch?v=EcrktBc8zrM

Video Solution by Interstigation

https://youtu.be/1bA7fD7Lg54?t=32

Video Solution by WhyMath

https://youtu.be/macEkeMMM_w

~savannahsolver

Video Solution by harungurcan

https://www.youtube.com/watch?v=35BW7bsm_Cg&t=10s

~harungurcan

2023 AMC 8 (Problems • Answer Key • Resources)
Preceded by First Problem	Followed by Problem 2
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

Revision as of 11:51, 26 October 2023 (view source) Math-x (talk \| contribs) ← Older edit		Revision as of 12:20, 26 October 2023 (view source) MRENTHUSIASM (talk \| contribs) (→‎Solution 2) Newer edit →
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	~MathFun1000		~MathFun1000
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	==Video Solution by Math-X (Smart and Simple)==		==Video Solution by Math-X (Smart and Simple)==

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