Difference between revisions of "2008 AMC 10B Problems/Problem 15"

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== Video Solution by OmegaLearn ==
 
== Video Solution by OmegaLearn ==

Revision as of 10:17, 8 October 2023

Problem

How many right triangles have integer leg lengths $a$ and $b$ and a hypotenuse of length $b+1$, where $b<100$?

$\mathrm{(A)}\ 6\qquad\mathrm{(B)}\ 7\qquad\mathrm{(C)}\ 8\qquad\mathrm{(D)}\ 9\qquad\mathrm{(E)}\ 10$

Solution

By the Pythagorean theorem, $a^2+b^2=b^2+2b+1$

This means that $a^2=2b+1$.

We know that $a,b>0$ and that $b<100$.

We also know that $a^2$ is odd and thus $a$ is odd, since the right side of the equation is odd. $2b$ is even. $2b+1$ is odd.

So $a=1,3,5,7,9,11,13$, but if $a=1,  then$b=0 Thus a≠1.

Thus $a=3,5,7,9,11,13$

The answer is $\boxed{A}$.


~qkddud

Video Solution by OmegaLearn

https://youtu.be/euz1azVKUYs?t=135

~ pi_is_3.14

See also

2008 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 14
Followed by
Problem 16
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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