Difference between revisions of "2017 AMC 12A Problems/Problem 1"

(Solution)
(Added another video solution)
 
Line 13: Line 13:
  
 
~Education, the Study of Everything
 
~Education, the Study of Everything
 +
 +
==Video Solution==
 +
https://www.youtube.com/watch?v=Ro_koxVqd50
 +
 +
~Math4All999
  
 
==See Also==
 
==See Also==

Latest revision as of 06:03, 14 September 2024

Problem

Pablo buys popsicles for his friends. The store sells single popsicles for $$1$ each, 3-popsicle boxes for $$2$, and 5-popsicle boxes for $$3$. What is the greatest number of popsicles that Pablo can buy with $$8$?

$\textbf{(A)}\ 8\qquad\textbf{(B)}\ 11\qquad\textbf{(C)}\ 12\qquad\textbf{(D)}\ 13\qquad\textbf{(E)}\ 15$

Solution

We can take two 5-popsicle boxes and one 3-popsicle box with $$8$. Note that it is optimal since one popsicle is at the rate of $$1$ per popsicle, three popsicles at $$\frac{2}{3}$ per popsicle and finally, five popsicles at $$\frac{3}{5}$ per popsicle, hence we want as many $$3$ sets as possible. It is clear that the above is the optimal method. $\boxed{\textbf{D}}$.

Video Solution (HOW TO THINK CREATIVELY!!!)

https://youtu.be/VYo0SaDaMVs

~Education, the Study of Everything

Video Solution

https://www.youtube.com/watch?v=Ro_koxVqd50

~Math4All999

See Also

2017 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions
2017 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png