Difference between revisions of "2018 AMC 8 Problems/Problem 7"

Revision as of 03:03, 29 December 2022

Problem

The $5$ -digit number $\underline{2}$ $\underline{0}$ $\underline{1}$ $\underline{8}$ $\underline{U}$ is divisible by $9$ . What is the remainder when this number is divided by $8$ ?

$\textbf{(A) }1\qquad\textbf{(B) }3\qquad\textbf{(C) }5\qquad\textbf{(D) }6\qquad\textbf{(E) }7$

Solution

We use the property that the digits of a number must sum to a multiple of $9$ if it are divisible by $9$ . This means $2+0+1+8+U$ must be divisible by $9$ . The only possible value for $U$ then must be $7$ . Since we are looking for the remainder when divided by $8$ , we can ignore the thousands. The remainder when $187$ is divided by $8$ is $\boxed{\textbf{(B) }3}$ .

20187 mod 8 =_ 3

Video Solution by OmegaLearn

https://youtu.be/6xNkyDgIhEE?t=2341

Video Solution

https://youtu.be/doHZiAT36BY

~savannahsolver

2018 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 6	Followed by Problem 8
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

@@ Line 10: / Line 10: @@
 mod 8 =_ 3
-==Video Solutions==
+==Video Solution by OmegaLearn==
 https://youtu.be/6xNkyDgIhEE?t=2341
+==Video Solution==
 https://youtu.be/doHZiAT36BY

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