Difference between revisions of "1992 AJHSME Problems/Problem 12"
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In the <math> 30,000 </math> miles, four tires were always used at one time, so the amount of miles the five tires were used in total is <math> 30,000 \times 4=120,000 </math>. Five tires were used and each was used equally, so each tire was used for <math> \frac{120,000}{5}=\boxed{\text{(C)}\ 24,000} </math>. | In the <math> 30,000 </math> miles, four tires were always used at one time, so the amount of miles the five tires were used in total is <math> 30,000 \times 4=120,000 </math>. Five tires were used and each was used equally, so each tire was used for <math> \frac{120,000}{5}=\boxed{\text{(C)}\ 24,000} </math>. | ||
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==See Also== | ==See Also== | ||
{{AJHSME box|year=1992|num-b=11|num-a=13}} | {{AJHSME box|year=1992|num-b=11|num-a=13}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Latest revision as of 16:21, 27 November 2022
Problem
The five tires of a car (four road tires and a full-sized spare) were rotated so that each tire was used the same number of miles during the first 
miles the car traveled. For how many miles was each tire used?
Solution
In the miles, four tires were always used at one time, so the amount of miles the five tires were used in total is 
. Five tires were used and each was used equally, so each tire was used for 
.
See Also
| 1992 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 11 |
Followed by Problem 13 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
