Difference between revisions of "2002 IMO Problems/Problem 2"

Revision as of 11:11, 7 October 2022

$\text{BC is a diameter of a circle center O. A is any point on the circle with } \angle AOC \not\le 60^\circ$

$\text{EF is the chord which is the perpendicular bisector of AO. D is the midpoint of the minor arc AB. The line through}$

$\text{O parallel to AD meets AC at J. Show that J is the incenter of triangle CEF.}$

$\text{By construction, AEOF is a rhombus with } 60^\circ - 120^\circ \text{angles}$

$\text{ Consequently, we may set } s = AO = AE = AF = EO = EF$

$\documentclass{article}

\usepackage[pdftex]{graphicx} \begin{document}

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@@ Line 7: / Line 7: @@
 :<math>\text{By construction, AEOF is a rhombus with } 60^\circ - 120^\circ \text{angles}</math>
 :<math>\text{ Consequently, we may set } s = AO = AE = AF = EO = EF</math>
-:<math>\documentclass{article} \usepackage[pdftex]{graphicx} \begin{document} \begin{center} \includegraphics{myimage.png} \end{center} \end{document}}</math>
+:<math>\documentclass{article}
+\usepackage[pdftex]{graphicx}
+\begin{document}
+This is my first image.
+\includegraphics{myimage.png}
+That's a cool picture up above.
+\end{document}</math>