Difference between revisions of "Proportion/Intermediate"

Revision as of 16:54, 9 October 2007

Problem

$x$ is directly proportional to the sum of the squares of $y$ and $z$ and inversely proportional to $y$ and the square of $z$ . If $x = 8$ when $y = 1/2$ and $z = \sqrt {3}/2$ , find $y$ when $x = 1$ and $z = 6$ .

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Difference between revisions of "Proportion/Intermediate"

Revision as of 16:54, 9 October 2007

Problem

Solution

Revision as of 16:54, 9 October 2007 (view source) Temperal (talk \| contribs) (add problem) ← Older edit	Revision as of 16:54, 9 October 2007 (view source) Temperal (talk \| contribs) m (User:Temperal/Intermediate Proportion moved to Proportion/Intermediate Proportion) Newer edit →
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