Difference between revisions of "2022 AMC 8 Problems/Problem 15"
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label(scale(0.7)*"$4$", (-0.3,4), black); | label(scale(0.7)*"$4$", (-0.3,4), black); | ||
label(scale(0.7)*"$5$", (-0.3,5), black); | label(scale(0.7)*"$5$", (-0.3,5), black); | ||
− | label(scale(0. | + | label(scale(0.8)*rotate(90)*"Price (dollars)", (-1,3.2), black); |
− | label(scale(0. | + | label(scale(0.8)*"Weight (ounces)", (3.2,-1), black); |
dot((1,1.2),black); | dot((1,1.2),black); | ||
dot((1,1.7),black); | dot((1,1.7),black); |
Revision as of 12:00, 2 February 2022
Contents
Problem
Laszlo went online to shop for black pepper and found thirty different black pepper options varying in weight and price, shown in the scatter plot below. In ounces, what is the weight of the pepper that offers the lowest price per ounce?
Solution
We are looking for a black point, that when connected to the origin, yields the lowest slope. The slope represents the price per ounce. It is clearly the blue point, which can be found visually. Also, it is the only one with a price per once significantly less than . Finally, we see that the blue point is over the category with a weight of ounces.
~MathFun1000
Remark
By the answer choices, we can disregard the points that do not have integer weights. As a result, we obtain the following diagram:
~DairyQueenXD
See Also
2022 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 14 |
Followed by Problem 16 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.