Difference between revisions of "2020 AMC 8 Problems/Problem 2"
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The friends earn <math>\$\left(15+20+25+40\right)=\$100</math> in total. Since they decided to split their earnings equally, it follows that each person will get <math>\$\left(\frac{100}{4}\right)=\$25</math>. Since the friend who earned <math>\$40</math> will need to leave with <math>\$25</math>, he will have to give <math>\$\left(40-25\right)=\boxed{\textbf{(C) }\$15}</math> to the others. | The friends earn <math>\$\left(15+20+25+40\right)=\$100</math> in total. Since they decided to split their earnings equally, it follows that each person will get <math>\$\left(\frac{100}{4}\right)=\$25</math>. Since the friend who earned <math>\$40</math> will need to leave with <math>\$25</math>, he will have to give <math>\$\left(40-25\right)=\boxed{\textbf{(C) }\$15}</math> to the others. | ||
==Solution2== | ==Solution2== | ||
| − | Because we seek the arethmetic mean of 15, 20, 25, and 40, (15+20+25+40)/4=<math>25. The friend with | + | Because we seek the arethmetic mean of 15, 20, 25, and 40, (15+20+25+40)/4=<math>25. The friend with 40 dollars will give </math>\$\left(40-25\right)=\boxed{\textbf{(C) }\$15}$ to the others. |
~strongstephen | ~strongstephen | ||
Revision as of 20:12, 10 January 2022
Contents
Problem
Four friends do yardwork for their neighbors over the weekend, earning 
and 
respectively. They decide to split their earnings equally among themselves. In total how much will the friend who earned 
give to the others?
Solution1
The friends earn 
in total. Since they decided to split their earnings equally, it follows that each person will get 
. Since the friend who earned will need to leave with 
, he will have to give 
to the others.
Solution2
Because we seek the arethmetic mean of 15, 20, 25, and 40, (15+20+25+40)/4=
$\left(40-25\right)=\boxed{\textbf{(C) }$15}$ to the others.
~strongstephen
Video Solution by WhyMath
~savannahsolver
Video Solution by North America Math Contest Go Go Go
https://www.youtube.com/watch?v=ZwfPEYd55NQ
~North America Math Contest Go Go Go
Video Solution
https://youtu.be/eSxzI8P9_h8 ~ The Learning Royal
Video Solution by Interstigation
https://youtu.be/YnwkBZTv5Fw?t=62
~Interstigation
See Also
| 2020 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
