Difference between revisions of "2006 AMC 8 Problems/Problem 21"
m (→Super Easy Solution) |
(→Solution) |
||
| Line 6: | Line 6: | ||
==Solution== | ==Solution== | ||
The water level will rise <math>1</math>cm for every <math>100 \cdot 40 = 4000\text{cm}^2</math>. Since <math>1000</math> is <math>\frac{1}{4}</math> of <math>4000</math>, the water will rise <math>\frac{1}{4}\cdot1 = \boxed{\textbf{(A)}\ 0.25}</math> | The water level will rise <math>1</math>cm for every <math>100 \cdot 40 = 4000\text{cm}^2</math>. Since <math>1000</math> is <math>\frac{1}{4}</math> of <math>4000</math>, the water will rise <math>\frac{1}{4}\cdot1 = \boxed{\textbf{(A)}\ 0.25}</math> | ||
| + | |||
| + | ==Video Solution== | ||
| + | |||
| + | https://www.youtube.com/watch?v=DNMuW5prOwg | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2006|n=II|num-b=20|num-a=22}} | {{AMC8 box|year=2006|n=II|num-b=20|num-a=22}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 14:18, 9 October 2022
Contents
Problem
An aquarium has a rectangular base that measures 
cm by 
cm and has a height of 
cm. The aquarium is filled with water to a depth of 
cm. A rock with volume 
is then placed in the aquarium and completely submerged. By how many centimeters does the water level rise?
Solution
The water level will rise 
cm for every 
. Since 
is 
of 
, the water will rise 
Video Solution
https://www.youtube.com/watch?v=DNMuW5prOwg
See Also
| 2006 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 20 |
Followed by Problem 22 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
