Difference between revisions of "2006 AMC 10B Problems/Problem 3"
Dairyqueenxd (talk | contribs) (→Solution) |
(→Solution) |
||
| Line 13: | Line 13: | ||
y &= \boxed{\textbf{(A) }10} \\ | y &= \boxed{\textbf{(A) }10} \\ | ||
\end{align*}</cmath> | \end{align*}</cmath> | ||
| + | |||
| + | == Solution 2 == | ||
| + | <math>c</math> is the amount the Cougars scored and <math>p</math> is the score for Panthers. Since the Cougars won by 14 points, <math>c = p + 14</math>. Using substitution, | ||
| + | <math>2p + 14 = 34</math> | ||
| + | <math>2p = 20</math> | ||
| + | <math>p = 10</math> | ||
| + | |||
| + | The answer is \boxed{\textbf{(A) }10} \\ | ||
== See Also == | == See Also == | ||
Revision as of 14:48, 21 February 2025
Contents
Problem
A football game was played between two teams, the Cougars and the Panthers. The two teams scored a total of 
points, and the Cougars won by a margin of 
points. How many points did the Panthers score?
Solution
Let 
be the number of points scored by the Cougars, and 
be the number of points scored by the Panthers. The problem is asking for the value of .
Solution 2
is the amount the Cougars scored and 
is the score for Panthers. Since the Cougars won by 14 points, 
. Using substitution,
The answer is \boxed{\textbf{(A) }10} \\
See Also
| 2006 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
