Difference between revisions of "2005 AMC 12A Problems/Problem 10"

(New page: == Problem == A wooden cube <math>n</math> units on a side is painted red on all six faces and then cut into <math>n^3</math> unit cubes. Exactly one-fourth of the total number of faces of...)
 
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== Problem ==
 
== Problem ==
A wooden cube <math>n</math> units on a side is painted red on all six faces and then cut into <math>n^3</math> unit cubes. Exactly one-fourth of the total number of faces of the unit cubes are red. What is <math>n</math>?  
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A wooden [[cube]] <math>n</math> units on a side is painted red on all six faces and then cut into <math>n^3</math> unit cubes. Exactly one-fourth of the total number of faces of the unit cubes are red. What is <math>n</math>?  
  
 
<math>
 
<math>
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</math>
 
</math>
 
== Solution ==
 
== Solution ==
There are <math>6n^3</math> sides total, and <math>6n^2</math> are painted red.
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There are <math>6n^3</math> sides total on the unit cubes, and <math>6n^2</math> are painted red.
  
 
<math>\dfrac{6n^2}{6n^3}=\dfrac{1}{4} \Rightarrow n=4 \rightarrow \mathrm {B}</math>
 
<math>\dfrac{6n^2}{6n^3}=\dfrac{1}{4} \Rightarrow n=4 \rightarrow \mathrm {B}</math>
 
 
  
 
== See also ==
 
== See also ==

Revision as of 13:02, 23 September 2007

Problem

A wooden cube $n$ units on a side is painted red on all six faces and then cut into $n^3$ unit cubes. Exactly one-fourth of the total number of faces of the unit cubes are red. What is $n$?

$(\mathrm {A}) \ 3 \qquad (\mathrm {B}) \ 4 \qquad (\mathrm {C})\ 5 \qquad (\mathrm {D}) \ 6 \qquad (\mathrm {E})\ 7$

Solution

There are $6n^3$ sides total on the unit cubes, and $6n^2$ are painted red.

$\dfrac{6n^2}{6n^3}=\dfrac{1}{4} \Rightarrow n=4 \rightarrow \mathrm {B}$

See also

2005 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions