Difference between revisions of "User:Temperal/Introductory Proportion"

m (Solution: \displaystyle)
(Solution)
Line 8: Line 8:
  
 
==Solution==
 
==Solution==
{{solution}}
 
  
if <math>x=\frac{1} {20}</math>, then <math>\displaystyle  \frac{y} {20} = \frac{1} {k}</math>.
+
If <math>x=\frac{1} {20}</math>, then <math>\displaystyle  \frac{y} {20} = \frac{1} {k}</math>.

Revision as of 20:50, 19 September 2007

Problem

Suppose $\displaystyle \frac{1}{20}$ is either x or y in the following system:

$\begin{cases} xy=\frac{1}{k}\\ x=ky \end{cases}$

Find the possible values of k.

Solution

If $x=\frac{1} {20}$, then $\displaystyle  \frac{y} {20} = \frac{1} {k}$.