Difference between revisions of "2017 JBMO Problems/Problem 2"

Revision as of 11:13, 22 July 2021

Problem

Let $x,y,z$ be positive integers such that $x\neq y\neq z \neq x$ .Prove that $(x+y+z)(xy+yz+zx-2)\geq 9xyz.$ When does the equality hold?

Solution

Since the equation is symmetric and $x,y,z$ are distinct integers WLOG we can assume that $x\geq y+1\geq z+2$ . $\begin{align*} x+y+z\geq 3(z+1)\\ xy+yz+xz-2 = y(x+z)+xy-2 \geq (z+1)(2z+z)+z(z+2)-2 \\ xy+yz+xz-2 \geq 3z(z+2) \end{align*}$ Hence $(x+y+z)(xy+yz+xz-2)\geq 9(z)(z+1)(z+2)$

@@ Line 12: / Line 12: @@
 \end{align*}</cmath>
 Hence <cmath>(x+y+z)(xy+yz+xz-2)\geq 9(z)(z+1)(z+2)</cmath>
-== Solution 2 ==
-Expanding the equation gives
-<cmath>x^2y + x^2z + y^2x+ y^2z + z^2x + z^2y</cmath>
 == See also ==

2017 JBMO (Problems • Resources)
Preceded by Problem 1	Followed by Problem 3
1 • 2 • 3 • 4
All JBMO Problems and Solutions

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Difference between revisions of "2017 JBMO Problems/Problem 2"

Revision as of 11:13, 22 July 2021

Problem

Solution

See also