Difference between revisions of "2021 JMPSC Accuracy Problems/Problem 1"

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== Solution ==
 
== Solution ==
  
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We use the fact that 27 = 2^3<math> to conclude that the only multiples of </math>3<math> that are factors of </math>27<math> are </math>3<math>, </math>9<math>, and </math>27<math>. Thus, our answer is </math>3+9+27=\boxed{39)$
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~Bradygho

Revision as of 20:56, 10 July 2021

Problem

Find the sum of all positive multiples of $3$ that are factors of $27.$

Solution

We use the fact that 27 = 2^3$to conclude that the only multiples of$3$that are factors of$27$are$3$,$9$, and$27$. Thus, our answer is$3+9+27=\boxed{39)$

~Bradygho