Difference between revisions of "2007 AMC 10A Problems/Problem 5"
(→Solution) |
(→Solution) |
||
Line 5: | Line 5: | ||
== Solution == | == Solution == | ||
− | We let <math>p =</math> cost of one pencil in | + | We let <math>p =</math> cost of one pencil in dollars, <math>n = </math> cost of one notebook in dollars. Then |
<cmath>\begin{align*} | <cmath>\begin{align*} |
Revision as of 11:07, 3 June 2021
Problem
The school store sells 7 pencils and 8 notebooks for . It also sells 5 pencils and 3 notebooks for . How much do 16 pencils and 10 notebooks cost?
Solution
We let cost of one pencil in dollars, cost of one notebook in dollars. Then
Subtracting these equations yields . Backwards solving gives . Thus the answer is .
See also
2007 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.