Difference between revisions of "2021 AMC 12A Problems/Problem 9"

Revision as of 13:52, 11 February 2021

These problems will not be posted until the 2021 AMC12A is released on Thursday, February 4, 2021.

2021 AMC 12A (Problems • Answer Key • Resources)
Preceded by Problem 8	Followed by Problem 10
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AMC 12 Problems and Solutions

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 These problems will not be posted until the 2021 AMC12A is released on Thursday, February 4, 2021.
 ==Solution==
-Expanding, we get that the expression is <math>x^2+2xy+y^2+x^2y^2-2xy+1</math> or <math>x^2+y^2+x^2y^2+1</math>. By the trivial inequality(all squares are nonnegative) the minimum value for this is <math>1</math>, which can be achieved at <math>x=y=0</math>. ~aop2014
 ==Note==