Difference between revisions of "2021 AMC 12A Problems/Problem 1"
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| − | = | + | So assume that 1 + 1 = 3 |
| − | + | ||
| + | Using this logic, prove that: | ||
| + | looking + at + this + problem = you're a cheater. | ||
| + | |||
==Solution== | ==Solution== | ||
The solutions will be posted once the problems are posted. | The solutions will be posted once the problems are posted. | ||
Revision as of 02:34, 31 January 2021
So assume that 1 + 1 = 3
Using this logic, prove that: looking + at + this + problem = you're a cheater.
Solution
The solutions will be posted once the problems are posted.
See also
| 2021 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by First problem |
Followed by Problem 2 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
