Difference between revisions of "2020 AMC 8 Problems/Problem 15"

Line 5: Line 5:
 
==Solution 1==
 
==Solution 1==
 
Multiply by <math>5</math> to get <math>75\% x=y</math>. Therefore, <math>\boxed{\textbf{C}}</math> is the answer.
 
Multiply by <math>5</math> to get <math>75\% x=y</math>. Therefore, <math>\boxed{\textbf{C}}</math> is the answer.
 +
 +
==See also==
 +
{{AMC8 box|year=2020|num-b=14|num-a=16}}
 +
{{MAA Notice}}

Revision as of 00:20, 18 November 2020

Suppose $15\%$ of $x$ equals $20\%$ of $y.$ What percentage of $x$ is $y?$

$\textbf{(A) }5 \qquad \textbf{(B) }35 \qquad \textbf{(C) }75 \qquad \textbf{(D) }133 \frac13 \qquad \textbf{(E) }300$

Solution 1

Multiply by $5$ to get $75\% x=y$. Therefore, $\boxed{\textbf{C}}$ is the answer.

See also

2020 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 14
Followed by
Problem 16
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png