Difference between revisions of "2001 AMC 8 Problems/Problem 12"
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<math> 6\otimes4=\frac{6+4}{6-4}=5 </math>. | <math> 6\otimes4=\frac{6+4}{6-4}=5 </math>. | ||
<math> 5\otimes3=\frac{5+3}{5-3}=4, \boxed{\text{A}} </math> | <math> 5\otimes3=\frac{5+3}{5-3}=4, \boxed{\text{A}} </math> | ||
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| + | ==Video Solution-Cooler Method== | ||
| + | https://www.youtube.com/watch?v=ZfwtAiH_6PI&t=36s | ||
==See Also== | ==See Also== | ||
Revision as of 20:42, 26 December 2023
Problem
If 
, then 
Solution
.
Video Solution-Cooler Method
https://www.youtube.com/watch?v=ZfwtAiH_6PI&t=36s
See Also
| 2001 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 11 |
Followed by Problem 13 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
