Difference between revisions of "2011 AMC 10B Problems/Problem 1"
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== Problem== | == Problem== | ||
| − | What is <cmath>\dfrac{2+4+6}{1+3+5} - \dfrac{1+3+5}{2+4+ | + | What is <cmath>\dfrac{2+4+6}{1+3+5} - \dfrac{1+3+5}{2+4+7} ?</cmath> |
<math> \textbf{(A)}\ -1\qquad\textbf{(B)}\ \frac{5}{36}\qquad\textbf{(C)}\ \frac{7}{12}\qquad\textbf{(D)}\ \frac{147}{60}\qquad\textbf{(E)}\ \frac{43}{3} </math> | <math> \textbf{(A)}\ -1\qquad\textbf{(B)}\ \frac{5}{36}\qquad\textbf{(C)}\ \frac{7}{12}\qquad\textbf{(D)}\ \frac{147}{60}\qquad\textbf{(E)}\ \frac{43}{3} </math> | ||
Revision as of 13:35, 8 November 2020
Contents
Problem
What is ![\[\dfrac{2+4+6}{1+3+5} - \dfrac{1+3+5}{2+4+7} ?\]](http://latex.artofproblemsolving.com/2/a/f/2af8c4bd76d36c37676ab6fc444a7c85f1f55954.png)
Solution
Note: This exact problem was reused in 2013 AMC 10B:
https://artofproblemsolving.com/wiki/index.php/2013_AMC_10B_Problems/Problem_1
Video Solution
~savannahsolver
See Also
| 2011 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
